Consider the reactions:
$(a)$ $H_3PO_{2(aq)} + 4AgNO_{3(aq)} + 2H_2O_{(l)} \to H_3PO_{4(aq)} + 4Ag_{(s)} + 4HNO_{3(aq)}$
$(b)$ $H_3PO_{2(aq)} + 2CuSO_{4(aq)} + 2H_2O_{(l)} \to H_3PO_{4(aq)} + 2Cu_{(s)} + H_2SO_{4(aq)}$
$(c)$ $C_6H_5CHO_{(l)} + 2[Ag(NH_3)_2]^+_{(aq)} + 3OH^-_{(aq)} \to C_6H_5COO^-_{(aq)} + 2Ag_{(s)} + 4NH_{3(aq)} + 2H_2O_{(l)}$
$(d)$ $C_6H_5CHO_{(l)} + 2Cu^{2+}_{(aq)} + 5OH^-_{(aq)} \to$ No change observed.
What inference do you draw about the behaviour of $Ag^+$ and $Cu^{2+}$ from these reactions?

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(N/A) In reactions $(a)$ and $(b)$,$H_3PO_2$ acts as a reducing agent,reducing $Ag^+$ and $Cu^{2+}$ to their metallic states,while $Ag^+$ and $Cu^{2+}$ act as oxidizing agents.
In reaction $(c)$,the Tollens' reagent ($Ag^+$ complex) successfully oxidizes benzaldehyde $(C_6H_5CHO)$ to benzoate ion $(C_6H_5COO^-)$.
In reaction $(d)$,$Cu^{2+}$ fails to oxidize benzaldehyde under the given conditions.
Therefore,we can infer that $Ag^+$ is a stronger oxidizing agent than $Cu^{2+}$.

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